Results for “Std.Concurrent.Retry.Policy”

Use module:Std.List, kind:fn, or is:exact. Put a Pudu type after ::.

• Std.Concurrent.Retry.Policy

  How often to try and how long to wait between tries. The wait before

  type · Std.Concurrent.Retry
• Std.Concurrent.Retry.ceiling&Std.Concurrent.Retry.Policy -> Int -> Int

  The wait before retry retry, before jitter. It multiplies only while the

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.delay&Std.Concurrent.Retry.Policy -> Int -> &Std.Random.Generator -> (Std.Random.Generator, Int)

  The jittered wait before retry retry, and the generator to draw from next.

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.run&Std.Concurrent.Retry.Policy -> fn(Int) -> Result[T, E] -> Result[T, Std.Concurrent.Retry.RetryError[E]]

  Run action until it succeeds or the attempts run out, retrying every

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.runCancellable&Std.Concurrent.Retry.Policy -> &Std.Concurrent.Cancel.Token -> fn(E) -> Bool -> fn(Int) -> Result[T, E] -> Result[T, Std.Concurrent.Retry.RetryError[E]]

  runWhen, stopping when the token fires: before each attempt and during

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.runWhen&Std.Concurrent.Retry.Policy -> fn(E) -> Bool -> fn(Int) -> Result[T, E] -> Result[T, Std.Concurrent.Retry.RetryError[E]]

  run, retrying only the failures retryable accepts; any other failure

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.standardStd.Concurrent.Retry.Policy

  Five attempts, waiting from 100 ms and doubling up to 10 s, fully jittered.

  fn · Std.Concurrent.Retry
• Std.Concurrent.Retry.validate&Std.Concurrent.Retry.Policy -> Result[(), Str]

  Why a policy cannot be followed, checked before any attempt.

  fn · Std.Concurrent.Retry