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Std.Option.mapPresent

1 declaration

fn

mapPresent: &Array[A] -> fn(A) -> Option[B] -> Array[B]

This is a callable function.

What it does

Every element transformed, keeping only the results that are present.

One pass rather than a map followed by a filter, which is why it exists.

Read the signature

  • The text after the name is the type checked by Pudu.
  • Read arrows from left to right: inputs come first, and the final type is returned.
  • & borrows a value for this call instead of moving or copying it.
  • Names inside [ ] are type arguments, such as the item type held by a collection.
  • Option holds Some(value) or None when no value is available.

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